pandas.tseries.offsets.Hour.is_quarter_end: Demystifying the Non-Existent Method
Data Offsets in pandas
pandas provides the Offset
class and its subclasses like Hour
to represent time-based increments for working with dates and times. These offsets allow you to efficiently shift dates or time series data by a specific amount of time.
Hour
Offset
The Hour
offset represents a time difference of one hour. You can use it to move a date or datetime object forward or backward by a certain number of hours. For instance:
import pandas as pd
date = pd.to_datetime('2024-07-07 10:00')
one_hour_later = date + pd.offsets.Hour(1) # Moves forward by 1 hour
print(one_hour_later) # Output: 2024-07-07 11:00:00
Hour.is_quarter_end
Method (Not Actually Available)
However, the Hour
offset class does not have a method called is_quarter_end
. This method is likely intended for the QuarterEnd
offset, which deals with quarter-based time increments.
QuarterEnd
Offset (For Checking Quarter Ends)
The QuarterEnd
offset represents the end of a quarter (March-May, June-August, September-November, December-February). It has a method named is_quarter_end
that you can use to check if a specific date or datetime object falls on a quarter end.
import pandas as pd
date = pd.to_datetime('2024-06-30') # June 30th, a quarter end
quarter_end_check = pd.offsets.QuarterEnd().is_quarter_end(date)
print(quarter_end_check) # Output: True
date = pd.to_datetime('2024-07-05') # Not a quarter end
quarter_end_check = pd.offsets.QuarterEnd().is_quarter_end(date)
print(quarter_end_check) # Output: False
QuarterEnd.is_quarter_end
: Checks if a date/datetime object falls on a quarter end.QuarterEnd
offset: Represents the end of a quarter.Hour.is_quarter_end
(non-existent): Not a valid method forHour
.Hour
offset: Represents an hour-based time difference.
Example 1: Moving Dates Forward by Hours and Checking for Quarter End
import pandas as pd
# Create a starting date
date = pd.to_datetime('2024-06-28') # Friday, June 28th
# Move forward 4 hours (within the same day)
four_hours_later = date + pd.offsets.Hour(4)
print(four_hours_later) # Output: 2024-06-28 16:00:00
# Check if the new date is still in the same quarter
is_same_quarter = pd.offsets.QuarterEnd().is_quarter_end(date) == pd.offsets.QuarterEnd().is_quarter_end(four_hours_later)
print(is_same_quarter) # Output: True (both dates are in Q2 2024)
# Move forward to the next day (potentially crossing a quarter boundary)
next_day = date + pd.offsets.Day(1)
print(next_day) # Output: 2024-06-29 (Saturday, June 29th)
# Check if the next day is in the same quarter
is_same_quarter = pd.offsets.QuarterEnd().is_quarter_end(date) == pd.offsets.QuarterEnd().is_quarter_end(next_day)
print(is_same_quarter) # Output: False (June 29th is in Q2, June 30th is the end of Q2)
- Moving to the next day (
next_day
) might cross a quarter boundary. We useQuarterEnd().is_quarter_end
to verify that they are not in the same quarter (June 29th is in Q2, June 30th is the end of Q2). - We create a starting date (
date
) and move it forward by 4 hours usingHour(4)
. Theis_same_quarter
check confirms that both dates are still within the same quarter (Q2 2024).
import pandas as pd
# Create a starting date within a quarter (e.g., July 1st)
date = pd.to_datetime('2024-07-01') # Monday, July 1st (Q3)
# Get the next quarter end date (September 30th)
next_quarter_end = pd.to_datetime('2024-09-30')
# Calculate the number of hours needed to reach the next quarter end
hours_to_next_quarter = (next_quarter_end - date).total_seconds() / 3600
# Print the number of hours (adjust for daylight saving time if needed)
print(f"Hours to next quarter end: {hours_to_next_quarter:.2f}") # Example output: 2160.00 (assuming no daylight saving time)
- We calculate the total seconds between the dates and convert them to hours using
total_seconds() / 3600
. The result represents the number of hours needed to reach the next quarter end. - We define the next quarter end date (
next_quarter_end
). - We start with a date within a quarter (
date
).
Using QuarterEnd Offset
- Use the
is_quarter_end
method on your hourly datetime object with theQuarterEnd
offset. This checks if the hourly datetime falls on a quarter end. - Create a
QuarterEnd
offset object.
import pandas as pd
date = pd.to_datetime('2024-06-30 10:00') # Hourly datetime
quarter_end_check = pd.offsets.QuarterEnd().is_quarter_end(date)
print(quarter_end_check) # True (June 30th is a quarter end)
date = pd.to_datetime('2024-07-01 12:00') # Not a quarter end
quarter_end_check = pd.offsets.QuarterEnd().is_quarter_end(date)
print(quarter_end_check) # False
Vectorized Check with floor and DatetimeIndex
- Check if the resulting values are equal to the quarter number for the last day of the quarter. This can be done using comparison or boolean indexing.
- Use
np.floor
(or a similar function) to ensure you get whole quarter numbers. - Use integer division by 3 (number of months in a quarter) to get the quarter number for each hour.
- Convert your hourly datetime data to a
DatetimeIndex
if it's not already one.
import pandas as pd
import numpy as np
data = pd.to_datetime(['2024-06-30 10:00', '2024-07-01 12:00', '2024-09-30 18:00'])
quarter_numbers = np.floor(data.month / 3)
is_quarter_end = quarter_numbers == data.dt.month.max() / 3
print(is_quarter_end) # True, False, True
- Performance
For large datasets, the vectorized approach usingDatetimeIndex
operations might be faster. However, readability might be slightly lower. - Clarity
TheQuarterEnd
offset withis_quarter_end
is more readable for simple checks.